(1/x-5)+(1/x+5)=(16/x^2-25

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Solution for (1/x-5)+(1/x+5)=(16/x^2-25 equation: 



(1/x-5)+(1/x+5)=(16/x^2-25

We move all terms to the left:

(1/x-5)+(1/x+5)-((16/x^2-25)=0



Domain of the equation: x-5)!=0

x∈R





Domain of the equation: x+5)!=0

x∈R





Domain of the equation: x^2-25)!=0

x∈R



We get rid of parentheses

1/x+1/x-((16/x^2-25)-5+5=0

We calculate fractions

We do not support expression: x^3

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